SAT Right triangles Question

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Question 1 · Hard · MathJune 2024 · Q22Right triangles and trigonometry · 0 solved

$\frac{1}{c x} = \frac{x}{152} + \frac{1}{c}$ In the given equation, $c$ is a constant. If the equation has exactly one solution, what is the value of $c$ ?

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SAT discriminant: how many solutions, without solving — When an SAT question asks for exactly one solution or no real solution, it is asking about b² − 4ac. Solving the quadratic is the slow way to get it wrong.