SAT Linear equations in one variable Question

The equation $h=\frac{9(v-273.15)}{5}+32$ gives the corresponding temperature $h$, in degrees Fahrenheit, of any substance that has a temperature of $v$ kelvins, where $v>0$. If a substance has a temperature of 467.33 degrees Fahrenheit, what is the corresponding temperature, in kelvins, of this substance?